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Uncategorized |
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Category: Uncategorized

Good Female O Level Chemistry tutor in Singapore- interview

If you do a simple google search, you will find that most chemistry tutors in Singapore are males. Today we feature an interview with one of the rare female O level chemistry tutor in Singapore – Miss Joyce, who has been tutoring Secondary school students for O level chemistry for the past 18 years. Interviewer:…
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October 25, 2017 0

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Intensive Courses for O and A Levels

July 26, 2017 0

As the O’Level exam is approaching, there are more questions enquired by the students. Give us some time & we will upload these questions for sharing ASAP! ???????? Students, continue to clarify your doubts as we work hard together to achieve our goal! ????

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October 19, 2016 0

Ms Joyce, one more question, can u explain to me? Q: Insoluble silver chloride is produced by the following reaction. AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq) (a) Write an ionic equation for the reaction. ​​​​​​ (b) Determine the mass of silver chloride formed when an excess if aqueous sodium chloride is added to 200 cm3 of 0.2 mol/dm3 of silver nitrate. Hi Sandra, pls see below for solutions: (a) Ag+ (aq) + Cl- (aq) → AgCl (s) (b) Mole ratio of AgNO3 to AgCl is 1:1 Given: Volume of silver nitrate = 200/1000 = 0.2 dm3 Concentration of silver nitrate = 0.2 mol/dm3 Mole of silver nitrate = Concentration x Volume = 0.2 x 0.2 = 0.04mol Hence, number of moles of silver chloride is 0.04 mol. Thus, Mass of silver chloride = Moles X Relative molecular mass = 0.04mol X 143.5 g/mol = 5.74g. Hope this helps! Feel free to contact us at 62894551 (Serangoon garden branch) or 64400553 (Katong branch) for more details ????

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October 19, 2016 0

Hi Ms Joyce, I have a question below that needs your help to explain to me. Q: When zinc carbonate is heated strongly, it decomposes. ZnCO3(s) → ZnO(s) + CO2(g) (a) Explain the meaning of (s) and (g). ​(b) Describe a test to show that carbon dioxide is produced during this reaction. ​​​​​​​​​ (c) What is the relative molecular mass of zinc carbonate? ​​​​​​ (d) Determine the maximum mass of zinc oxide which can be obtained from 16.2g of zinc carbonate. Hi Sandra, please kindly see below for my solution: 3. (a) (s) means solid state and (g) means gaseous state. These are state symbols in a chemical question. (b) Test with limewater. A white precipitate is formed if carbon dioxide is present. (c) ZnCO3 = 65 + 12 + (3)(16) = 125 (simply sum up all the relative atomic masses of every elements present in the compound) (d) Moles of ZnCO3 = 16.2g / 125 g/mol = 0.1296mol Moles of ZnO = Moles of ZnCO3 since the mole ratio of ZnO : ZnCO3 is 1:1. Mass of ZnO = Moles X Relative molecular mass of ZnO = (0.1296 mol)(81 g/mol) = 10.5 g Hope these help! ???? Feel free to contact us at 62894551 (Serangoon garden branch) or 64400553 (Katong branch) if u need to look for the teacher for more details.

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October 19, 2016 0

Hi Teacher Joyce, I’m Angela, pls explain to me on Q25. Thanks! Hi Angela, pls see attach for the solution ????

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October 6, 2016 0

Hi Ms Joyce, need help on this question too! Hi Maier, pls see attach picture for the solution ????

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October 6, 2016 0

Teacher, can u help to solve this question on back titration? I’m Marcus from sec 3 IP chemistry class from Katong branch. Thanks! Marcus, kindly refer to my worked solution in the attach picture. If u have question, we can discuss it in the class on this Sunday. ????

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September 15, 2016 0

All the best to Students who are sitting for N’level exam today! Put in the best & U can do it! ????????????

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September 12, 2016 0

Teacher, pls help me with question part a) & part c). Thank you! Hi Marc, for part a) the equation is N2 + O2 -> NO2. In the engine of the motor vehicle, due to the high operating temperature, oxygen & nitrogen gases from the surrounding atmosphere will react to produce nitrogen dioxide in the internal combustion of the engines. For part c), amount of sulfur dioxide produced from vehicle A = 16.5% X 1kg = 0.165kg and amount of Sulfur dioxide produced from vehicle B = 6.9% X 1kg = 0.069kg. Hence, vehicle A produces greater amount of Sulfur dioxide than vehicle B & thus, vehicle A contributes more towards acid rain to the environment. You got it? ????

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September 9, 2016 0

Our O’ & A’ level students are now mugging hard for their prelims & final exams. Put in your best effort as we believe that you can do it! Continue to post your queries in class or in whatsapp & we will try our best to help ????✌️????????????

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August 19, 2016 0

Our O’ & A’ level students are now mugging for their prelims & the final exams! Best in your best effort as we believe that U can do it! Continue to post your questions here or in whatsapp & our teachers will answer them ????????✌️????

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August 19, 2016 0

Hi Ms Lee, can u explain this question to me? How to solve it? Thanks. Hi Benjamin, pls refer to my solution below. The same amount of charge means that the same number of moles of electrons, which is 0.5 moles, are involved in both the electrolysis experiments. Using mole ratios, u will be able to find the charge of tin ion. ????

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August 17, 2016 0

Hi Ms Joyce, can u kindly help me with this question? Hi Marcus, here’s the solution. Hope it helps! ????

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August 12, 2016 0

Hi Teacher, Another question, pls kindly help to solve & explain to me ???? Hi Angela, here’s the solution. Feel free to ask if u have any queries ????

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August 10, 2016 0

Hi Teacher, can u help me with this question? Thanks! ???? Hi Angela, here’s the solution. Firstly, u need to find the number of moles of lipoyl groups in the body fluid by multiplying the concentration with the mass of body fluid. Since the mole ratio between the amount of lead & the lipoyl groups in body is 1:1, the number of moles of lead is the same as the number of moles of lipoyl groups. Hence, to find the mass of lead, multiply the moles of lead by its atomic mass & u will derive the answer as C. ✌️

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August 10, 2016 0

Hi teacher, can u help me with this? Hi Angela,v sorry for the late reply. Here are the answers which I had drawn the structural formulae. This question is similar to one of the questions in worksheet 6.7 which we will be going thro during the ongoing lessons ???? hope this helps!

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August 2, 2016 0

After the long June holiday break, School has resumed for the past two weeks & we are getting more queries from the students as they are working harder for the 2nd half of the year ???? we will continue to post these questions here so that other students can also learn. Keep going everyone & you can do it! ????✌️????

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July 10, 2016 0

IP chemistry question from Mervin. Teacher, can u solve this question? Thks! Ok Mervin, here’s the answers. a.) W is Iron(III) oxide, T is sulfuric acid. b.) The type of reaction in step II is neutralization. The chemical equation is Fe2O3 + H2SO4 -> Fe2(SO4)3 + H2O. c.) The observation is reddish brown ppt will be formed insoluble in excess sodium hydroxide. d) To obtain brown crystals of G, heat the yellow solution of G to saturation and leave it to cool for crystallization to take place. Brown crystal of G will be formed gradually & filter the mixture to obtain crystal of G. Wash the crystals with cold distilled water & dry between filter papers. Got it?????

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June 20, 2016 0

IP chemistry question from Marcus ???? Hi Ms Lee, could u help me on this question? Thanks a lot! Hi Marcus, sorry for late reply as We are busy conducting holiday intensive courses these few days. Here’s the answer for the 1st question: b(i) pls see next image. For b(ii), the conductance decreases as more sulfuric acid is added. This is because, Barium sulfate which is an insoluble salt is forming as more acid is added. Hence, the amount of mobile ions present for electrical conductivity is decreasing when more acid is added. At the lowest conductance, all the alkali has been fully neutralized by sulfuric acid & maximum amount of insoluble barium sulfate salt has been formed. As more sulfuric acid continue to be added, the excess acid produces mobile ions which account for the increasing conductance. For b(iii), The pH decreases as sulfuric acid is added. Hope this helps! ????✌️

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June 20, 2016 0

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